Price: $19.95 - $16.39
(as of Sep 01, 2025 04:56:05 UTC – Details)
While cancer is certainly no laughing matter, in 100 Perks of Having Cancer: Plus 100 Health Tips for Surviving It, cancer survivors Florence Strang and Susan Gonzalez set out to remind readers that no matter how bad one’s life circumstances may be, there are always reasons to smile and steps that can be taken to improve one’s health, outlook, and prognosis.
Chock-full of healthy-living tips to promote healing of the body as well as perks to guide readers on healing the mind and soul, 100 Perks of Having Cancer is the perfect resource for anyone wanting to live healthier and happier. Whether the reader is currently battling cancer, is a cancer survivor, or is trying to avoid cancer, he or she will find applicable ideas and advice delivered in a friendly, relatable manner. Offering a plethora of hope and support, Strang and Gonzalez help readers approach cancer proactively and with survival in mind.
Publisher : Basic Health Publications
Publication date : August 2, 2013
Edition : First Edition
Language : English
Print length : 500 pages
ISBN-10 : 1591203562
ISBN-13 : 978-1591203568
Item Weight : 1.75 pounds
Dimensions : 7.7 x 1 x 9 inches
Best Sellers Rank: #2,416,926 in Books (See Top 100 in Books) #1,125 in Breast Cancer (Books) #2,936 in Holistic Medicine (Books) #5,325 in Healing
Customer Reviews: 4.7 4.7 out of 5 stars 68 ratings var dpAcrHasRegisteredArcLinkClickAction; P.when(‘A’, ‘ready’).execute(function(A) { if (dpAcrHasRegisteredArcLinkClickAction !== true) { dpAcrHasRegisteredArcLinkClickAction = true; A.declarative( ‘acrLink-click-metrics’, ‘click’, { “allowLinkDefault”: true }, function (event) { if (window.ue) { ue.count(“acrLinkClickCount”, (ue.count(“acrLinkClickCount”) || 0) + 1); } } ); } }); P.when(‘A’, ‘cf’).execute(function(A) { A.declarative(‘acrStarsLink-click-metrics’, ‘click’, { “allowLinkDefault” : true }, function(event){ if(window.ue) { ue.count(“acrStarsLinkWithPopoverClickCount”, (ue.count(“acrStarsLinkWithPopoverClickCount”) || 0) + 1); } }); });
